y^2+1=2y-10

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Solution for y^2+1=2y-10 equation:


Simplifying
y2 + 1 = 2y + -10

Reorder the terms:
1 + y2 = 2y + -10

Reorder the terms:
1 + y2 = -10 + 2y

Solving
1 + y2 = -10 + 2y

Solving for variable 'y'.

Reorder the terms:
1 + 10 + -2y + y2 = -10 + 2y + 10 + -2y

Combine like terms: 1 + 10 = 11
11 + -2y + y2 = -10 + 2y + 10 + -2y

Reorder the terms:
11 + -2y + y2 = -10 + 10 + 2y + -2y

Combine like terms: -10 + 10 = 0
11 + -2y + y2 = 0 + 2y + -2y
11 + -2y + y2 = 2y + -2y

Combine like terms: 2y + -2y = 0
11 + -2y + y2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-11' to each side of the equation.
11 + -2y + -11 + y2 = 0 + -11

Reorder the terms:
11 + -11 + -2y + y2 = 0 + -11

Combine like terms: 11 + -11 = 0
0 + -2y + y2 = 0 + -11
-2y + y2 = 0 + -11

Combine like terms: 0 + -11 = -11
-2y + y2 = -11

The y term is -2y.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2y + 1 + y2 = -11 + 1

Reorder the terms:
1 + -2y + y2 = -11 + 1

Combine like terms: -11 + 1 = -10
1 + -2y + y2 = -10

Factor a perfect square on the left side:
(y + -1)(y + -1) = -10

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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